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16.1t^2-44.4t-14=0
a = 16.1; b = -44.4; c = -14;
Δ = b2-4ac
Δ = -44.42-4·16.1·(-14)
Δ = 2872.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44.4)-\sqrt{2872.96}}{2*16.1}=\frac{44.4-\sqrt{2872.96}}{32.2} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44.4)+\sqrt{2872.96}}{2*16.1}=\frac{44.4+\sqrt{2872.96}}{32.2} $
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